How to solve this equation: e^(4x)+3e^(2x)-28=0 I don't know how to solve this problem. I read over another example, e^(2x)−2e^x−8=0, and it said that e^(2x) is e to the x squared, so e^(2x)=ex^2. Why is this so? So e^(4x)=e^(x^4)? Please help me to solve it.

Raina Gomez 2022-09-20 Answered
Solving e 4 x + 3 e 2 x 28 = 0
How to solve this equation:
e 4 x + 3 e 2 x 28 = 0
I don't know how to solve this problem. I read over another example, e 2 x 2 e x 8 = 0 , and it said that e 2 x is e to the x squared, so e 2 x = e x 2 . Why is this so? So e 4 x = e x 4 ?
Please help me to solve it.
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Answers (2)

Wischarm1q
Answered 2022-09-21 Author has 7 answers
Hint:
e 4 x + 3 e 2 x 28 = 0 ( e 2 x ) 2 + 3 ( e 2 x ) 28 = 0 e 2 x = x =
And I think what " e to the x squared" means is ( e x ) 2 , in this case it is equal to e 2 x since one have ( a m ) n = a m n .

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saucletbh
Answered 2022-09-22 Author has 3 answers
( e 2 x ) 2 + 3 e 2 x 28 = 0
u 2 + 3 u 28 = 0
This is a quadratic equation. Once you've found u, you've got e 2 x . After that, find x.

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