Logorithms on a first level learning

Solve log${}_{5x-1}$ $4$$=$$1/3$

$(5x-1{)}^{1/3}$=4

$((5x-1{)}^{1/3}{)}^{3}$ = ${4}^{3}$

$5x-1=64$

$5x=65$

$13$

I am not sure where to go with this. I learned some things about logs before my class ended for the year. I just wanted to expand on my knowledge. This is more advance than what I am use to doing. Can someone please show me.

Solve log${}_{5x-1}$ $4$$=$$1/3$

$(5x-1{)}^{1/3}$=4

$((5x-1{)}^{1/3}{)}^{3}$ = ${4}^{3}$

$5x-1=64$

$5x=65$

$13$

I am not sure where to go with this. I learned some things about logs before my class ended for the year. I just wanted to expand on my knowledge. This is more advance than what I am use to doing. Can someone please show me.