I'm supposed to find asymptotes for x⋅arctan(x) for a homework assignment. Are there any theorems regarding this I can utilize to find the equation for the asymptotes, or is this one of those solve case by case things, where this particular equation can be solved in some neat way, but there is no easy universal way to find asymptotes like this? I know it should be: +- pi/2 x−1 but "how do I show this?" is essentially my question. Thanks in advance

besnuffelfo 2022-09-20 Answered
How to find asymptotes
I'm supposed to find asymptotes for x⋅arctan(x) for a homework assignment.
Are there any theorems regarding this I can utilize to find the equation for the asymptotes, or is this one of those solve case by case things, where this particular equation can be solved in some neat way, but there is no easy universal way to find asymptotes like this?
I know it should be:
± π 2 x 1
but "how do I show this?" is essentially my question.
Thanks in advance
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Answers (1)

ululatonh
Answered 2022-09-21 Author has 1 answers
I am sure the following is in your textbook and/or has been explained in class.
Let f : R R be a function.
1. If lim x + f ( x ) = a, then y=a is a horizontal asymptote (similarly for x .)
2. If for some b R lim x b + f ( x ) = ± , then x=b is a vertical asymptote (similarly for x b .)
3. If lim x + f ( x ) x = m, and lim x + ( f ( x ) m x ) = c then y=mx+c is an oblique asymptote similarly for x .)
Apply it to xarctanx. The only difficulty is finding lim x x ( arctan x π 2 ), which can be done using L'Hôpital's rule.
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