# We Consider the following function f(x)=-3x^2+6x+1 Find the vertex of f.

We Consider the following function $f\left(x\right)=-3{x}^{2}+6x+1$
Find the vertex of f.
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Bridger Hall
Given $f\left(x\right)=-3{x}^{2}+6x+1$
If is a parabola which open downwards

vertex $f=\left(h,k\right)\phantom{\rule{0ex}{0ex}}h=-\frac{b}{2a}⇒\frac{-6}{2\left(-3\right)}=1\phantom{\rule{0ex}{0ex}}k=f\left(h\right)=f\left(1\right)=-3+6+1\phantom{\rule{0ex}{0ex}}=4\phantom{\rule{0ex}{0ex}}$