Simplify ((0.81)^2 xx (0.6xx0.21)^2)/(35^5 xx 0.252) into 2^n xx 3^m xx 5^p xx 7^k where n,m,p,k are integers.

Marcus Bass 2022-09-20 Answered
Simplify   ( 0.81 ) 2 × ( 0.6 × 0.21 ) 2 35 5 × 0.252 into 2 n × 3 m × 5 p × 7 k where n,m,p,k are integers.
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Answers (1)

soporoseun
Answered 2022-09-21 Author has 8 answers
( 0.81 ) 2 × ( 0.6 × 0.21 ) 2 35 5 × 0.252
( 81 100 ) 2 × ( 3 5 × 21 100 ) 2 ( 5 × 7 ) 5 × 63 250
( 3 4 × 2 2 × 5 2 ) 2 × ( 3 2 × 7 × 2 2 × 5 3 ) 2 5 5 × 7 5 × 7 × 3 2 × 2 1 × 5 3
3 8 × 2 4 × 5 4 × 3 4 × 7 2 × 2 4 × 5 6 2 1 × 3 2 × 5 2 × 7 6
2 8 × 3 12 × 5 10 × 7 2 2 1 × 3 2 × 5 2 × 7 6 = 2 8 × 3 12 × 5 10 × 7 2 × 2 1 × 3 2 × 5 2 × 7 6 = 2 7 × 3 10 × 5 12 × 7 4

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