Find the volume of the solid bounded by

${x}^{2}+{y}^{2}\u20132y=0,z={x}^{2}+{y}^{2},z=0$. I have to calculate volume using triple integrals but I struggle with finding intervals. I calculated ${x}_{1}=\sqrt{2y-{y}^{2}}$ and ${x}_{2}=-\sqrt{2y-{y}^{2}}$. I think z will have interval from 0 to 2y, but I don't know what to do next.

${x}^{2}+{y}^{2}\u20132y=0,z={x}^{2}+{y}^{2},z=0$. I have to calculate volume using triple integrals but I struggle with finding intervals. I calculated ${x}_{1}=\sqrt{2y-{y}^{2}}$ and ${x}_{2}=-\sqrt{2y-{y}^{2}}$. I think z will have interval from 0 to 2y, but I don't know what to do next.