Let the angle at vertex A be called alpha. Polya says by looking at the diagram and the isoceles triangles triangle ACE and triangle ABD we can deduce that angle DAE=alpha/2+90^circ.

deiluefniwf 2022-09-16 Answered
How is this angle measured in the triangle?
Given the image below:

Let the angle at vertex A be called α. Polya says by looking at the diagram and the isoceles triangles A C E and A B D we can deduce that D A E = α 2 + 90 ° .
Where will I get 90 ° from?
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Answers (2)

devilvunga
Answered 2022-09-17 Author has 14 answers
Step 1
D A E = E A C + D A B + α
= 180 ° A C E 2 + 180 ° A B D 2 + α
= A C B + A B C 2 + α
Step 2
= 180 ° α 2 + α
= 90 ° + α 2

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Hana Buck
Answered 2022-09-18 Author has 2 answers
Step 1
Exterior angle of triangle = sum of 2 interior opposite angles
A C B = 2 E A C A B C = 2 D A B
Step 2
E A C + D A B = 0.5 ( A C B + A B C ) = 0.5 ( 180 α )
D A E = 90 0.5 α + α

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