Let p be the number of pumpkins and ss be the number of squash they sold.

Since they sell each pumpkin for $5, they will earn 5p dollars selling pp pumpkins. Since they sell each squash for $3, they will earn 3s dollars selling ss squash. The total amount they will earn is then \(5p+3s\). If their sales totaled $98, then \(5p+3s=98\).

If they sold 6 more squash than pumpkins, then the number of squash they sold, s, is 6 more than the number of pumpkins they sold, p. This gives the equation \(s=6+p\).

You then have the system \(\{5p+3s=98,s=6+p\}\). Since the second equation is already solved for p you should use the substitution method to solve.

Substitute \(s=6+p\) into \(5p+3s=98\) and solve for p:

\(5p+3s=98\)

\(5p+3(6+p)=98\)

\(5p+18+3p=98\)

\(8p+18=98\)

\(8p=80\)

\(p=10\)

The vegetable stand then sold \(p=10\) pumpkins and \(s=6+p=6+10=16\) squash.