Let p be the number of pumpkins and ss be the number of squash they sold.

Since they sell each pumpkin for $5, they will earn 5p dollars selling pp pumpkins. Since they sell each squash for $3, they will earn 3s dollars selling ss squash. The total amount they will earn is then 5p+3s. If their sales totaled $98, then 5p+3s=98.

If they sold 6 more squash than pumpkins, then the number of squash they sold, s, is 6 more than the number of pumpkins they sold, p. This gives the equation s=6+p.

You then have the system {5p+3s=98,s=6+p}. Since the second equation is already solved for p you should use the substitution method to solve.

Substitute s=6+p into 5p+3s=98 and solve for p:

5p+3s=98

5p+3(6+p)=98

5p+18+3p=98

8p+18=98

8p=80

p=10

The vegetable stand then sold p=10 pumpkins and s=6+p=6+10=16 squash.

Since they sell each pumpkin for $5, they will earn 5p dollars selling pp pumpkins. Since they sell each squash for $3, they will earn 3s dollars selling ss squash. The total amount they will earn is then 5p+3s. If their sales totaled $98, then 5p+3s=98.

If they sold 6 more squash than pumpkins, then the number of squash they sold, s, is 6 more than the number of pumpkins they sold, p. This gives the equation s=6+p.

You then have the system {5p+3s=98,s=6+p}. Since the second equation is already solved for p you should use the substitution method to solve.

Substitute s=6+p into 5p+3s=98 and solve for p:

5p+3s=98

5p+3(6+p)=98

5p+18+3p=98

8p+18=98

8p=80

p=10

The vegetable stand then sold p=10 pumpkins and s=6+p=6+10=16 squash.