Step 1

From the provided information,

Level of significance \((\alpha) = 0.05\)

F (3, 26) = 3.00

The critical value of F at 3 and 26 degrees of freedom from the F value is 2.98.

Since, the test statistic value is greater than critical value, therefore, the null hypothesis will be rejected.

Step 2

F (4, 55) = 2.54

The critical value of F at 4 and 55 degrees of freedom from the F value is 2.54.

Since, the test statistic value is equal to the critical value, therefore, the null hypothesis will fail to reject.

Step 3

F (4, 30) = 2.72

The critical value of F at 4 and 30 degrees of freedom from the F value is 2.69.

Since, the test statistic value is greater than critical value, therefore, the null hypothesis will be rejected.

Step 4

F (2, 12) = 3.81

The critical value of F at 4 and 55 degrees of freedom from the F value is 3.89.

Since, the test statistic value is less than critical value, therefore, the null hypothesis will fail to reject.

From the provided information,

Level of significance \((\alpha) = 0.05\)

F (3, 26) = 3.00

The critical value of F at 3 and 26 degrees of freedom from the F value is 2.98.

Since, the test statistic value is greater than critical value, therefore, the null hypothesis will be rejected.

Step 2

F (4, 55) = 2.54

The critical value of F at 4 and 55 degrees of freedom from the F value is 2.54.

Since, the test statistic value is equal to the critical value, therefore, the null hypothesis will fail to reject.

Step 3

F (4, 30) = 2.72

The critical value of F at 4 and 30 degrees of freedom from the F value is 2.69.

Since, the test statistic value is greater than critical value, therefore, the null hypothesis will be rejected.

Step 4

F (2, 12) = 3.81

The critical value of F at 4 and 55 degrees of freedom from the F value is 3.89.

Since, the test statistic value is less than critical value, therefore, the null hypothesis will fail to reject.