# What is the range if f(x) = 3x - 9 and domain: -4,-3,0,1,8?

What is the range if f(x) = 3x - 9 and domain: -4,-3,0,1,8?
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Ronan Rollins
Explanation:
to obtain the range substitute the given values in the domain into f(x)
f(-4)=-12-9=-21
f(-3)=-9-9=-18
f(0)=-9
f(1)=3-9=-6
f(8)=24-9=15
range is $y\in \left\{-21,-18,-9,-6,15\right\}$

Diana Suarez
Here we have a lineal function f(x)=3x-9 defined for x={-4,-3,0,1,8}
The slope of $f\left(x\right)=3\to f\left(x\right)$ is linear increasing.
Since f(x) is linear increasing, its minimum and maximum values will be at the minimum and maximum values in its domain.
$\therefore {f}_{min}=f\left(-4\right)=-21$
and ${f}_{max}=f\left(8\right)=15$
The other values of f(x) are:
f(-3)=-18
f(0)=-9
f(1)=-6
Hence the range of f(x) is {-21, -18, -9, -6, +15}