Find all vertical and horizontal asymptotes: f(x)=4x/x^2+16 My Work: (Vertical) 1) x^2+16=0 2) x^2=−16 3) not possible so there is no vertical asymptote

likovnihuj

likovnihuj

Answered question

2022-09-15

Find all vertical and horizontal asymptotes.
Find all vertical and horizontal asymptotes:
f ( x ) = 4 x x 2 + 16
My Work: (Vertical)
1) x 2 + 16 = 0
2) x 2 = 16
3) not possible so there is no vertical asymptote
My Work: (Horizontal)
1) 4 x / x 2
2) 4/x
3) What do I do from here?

Answer & Explanation

Wischarm1q

Wischarm1q

Beginner2022-09-16Added 7 answers

Vertical asymptote: the only undefined output of f(x) is at x=0.
Consider x 0:
lim x 0 ( 4 x x 2 + 16 ) = lim x 0 ( 4 x + 16 ) =
and so x=0 is an asymptote.
Horizontal asymptote:
lim x ( 4 x x 2 + 16 ) = lim x 4 x + 16 = 16
and so y=16 is another asymptote.
Horizontal asymptote:
lim x 4 x x 2 + 16 = lim x 4 / x 1 + 16 / x 2 = 0
and so y=0 is another asymptote.

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