What is the distance between (13,-13,1) and (22,-1,6)?

memLosycecyjz
2022-09-17
Answered

What is the distance between (13,-13,1) and (22,-1,6)?

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r2t1orrso

Answered 2022-09-18
Author has **4** answers

For the distance between two points on a three-dimensional graph, the following formula is used:

$d=\left|\sqrt{{({x}_{2}-{x}_{1})}^{2}+{({y}_{2}-{y}_{1})}^{2}+{({z}_{2}-{z}_{1})}^{2}}\right|$

Here, $({x}_{1},{y}_{2},{z}_{1})=(13,-13,1)$ and $({x}_{2},{y}_{2},{z}_{2})=(22,-1,6)$

Inputting:

$d=\left|\sqrt{{(22-13)}^{2}+{(-1-(-13))}^{2}+{(6-1)}^{2}}\right|$

$d=\left|\sqrt{{9}^{2}+{12}^{2}+{5}^{2}}\right|$

$d=\left|\sqrt{250}\right|$

$d=15.81$ units

$d=\left|\sqrt{{({x}_{2}-{x}_{1})}^{2}+{({y}_{2}-{y}_{1})}^{2}+{({z}_{2}-{z}_{1})}^{2}}\right|$

Here, $({x}_{1},{y}_{2},{z}_{1})=(13,-13,1)$ and $({x}_{2},{y}_{2},{z}_{2})=(22,-1,6)$

Inputting:

$d=\left|\sqrt{{(22-13)}^{2}+{(-1-(-13))}^{2}+{(6-1)}^{2}}\right|$

$d=\left|\sqrt{{9}^{2}+{12}^{2}+{5}^{2}}\right|$

$d=\left|\sqrt{250}\right|$

$d=15.81$ units

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