How do you find the zeros of f(x)=(x^2−3x−4)/(x^2−x−12)?

teevaituinomakw 2022-09-15 Answered
How do you find the zeros of f ( x ) = x 2 - 3 x - 4 x 2 - x - 12 ?
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Answers (1)

enreciarpv
Answered 2022-09-16 Author has 18 answers
Factorising and simplifying f(x) as follows.
f ( x ) = x 2 - 3 x - 4 x 2 - x - 12 = ( x - 4 ) ( x + 1 ) ( x - 4 ) ( x - 3 ) = x + 1 x - 3
with exclusion x ≠ 4
The zeros of f(x) are the values of x which make f(x) equal zero. That is f(x)=0.
For f ( x ) = x + 1 x + 3
The denominator of f(x) cannot be zero as this would make f(x) undefined. The numerator is the only part of the rational function that can equal zero.
x + 1 = 0 x = - 1 is the zero of f(x)

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