# Second-degree, with zeros of −1−1 and 66, and goes to −∞−∞ as x→−∞.

Second - degree, with zeros of -1 -1 and 66, and goes to $-\mathrm{\infty }-\mathrm{\infty }$ as $x\to -\mathrm{\infty }$
You can still ask an expert for help

• Questions are typically answered in as fast as 30 minutes

Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it

cerfweddrq
Solution:
The Second degree, polynomial, the zero are x=1-1 abd 66=-2 and 66. Then the factors are (x+2)(x+66)
$y=\left(x+2\right)\left(x-66\right)={x}^{2}+2x-66x-132={x}^{2}-64x-132$
For the condition that, $y\to -\mathrm{\infty }$ as $x\to -\mathrm{\infty }$ we require the coefficient of ${x}^{2}$ to be negetive, $y=-{x}^{2}+64x+132$, is the required polynomial.