sincsenekdq
2022-09-16
Answered

Third-degree, with zeros of −3−3, −2−2, and 11, and passes through the point (3,6)(3,6).

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Nelson Santana

Answered 2022-09-17
Author has **13** answers

if C is the zero of a polynomial function f(x), then x-c is a factor of f(x)

f(n) has -3,-2,11 of a zeros.

So

$$f(x)=a(x+3)(x+2)(x-11)\phantom{\rule{0ex}{0ex}}f(3)=6\phantom{\rule{0ex}{0ex}}6=a(6)(5)(-Q)\phantom{\rule{0ex}{0ex}}a=\frac{-1}{90}\phantom{\rule{0ex}{0ex}}f(x)=-\frac{1}{90}(x+3)(x+2)(x-11)$$

f(n) has -3,-2,11 of a zeros.

So

$$f(x)=a(x+3)(x+2)(x-11)\phantom{\rule{0ex}{0ex}}f(3)=6\phantom{\rule{0ex}{0ex}}6=a(6)(5)(-Q)\phantom{\rule{0ex}{0ex}}a=\frac{-1}{90}\phantom{\rule{0ex}{0ex}}f(x)=-\frac{1}{90}(x+3)(x+2)(x-11)$$

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