How to you find the general solution of ylnx−xy'=0?

yrealeq
2022-09-14
Answered

How to you find the general solution of ylnx−xy'=0?

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asked 2022-09-09

What is the particular solution of the differential equation $y\prime +y\mathrm{tan}x=\mathrm{sin}\left(2x\right)$ where y(0)=1?

asked 2022-02-15

However, neither of the two integrating factors give functions of a variable alone. So what is left to do to solve this?

Thank you so much!

asked 2022-07-08

Solve the differential equation

$3y\phantom{\rule{thinmathspace}{0ex}}dx-x(3{x}^{n}y\mathrm{sin}y+3)\phantom{\rule{thinmathspace}{0ex}}dy=0.$

I need to find the general solution for both $n=0$ and $n=3$. So, for $n=0$ is done because the differential equation becomes a separable equation. However, I can't find a solution for $n=3$ because it is not a Bernoulli equation nor an exact DE. If someone could help me, it would be great.

$3y\phantom{\rule{thinmathspace}{0ex}}dx-x(3{x}^{n}y\mathrm{sin}y+3)\phantom{\rule{thinmathspace}{0ex}}dy=0.$

I need to find the general solution for both $n=0$ and $n=3$. So, for $n=0$ is done because the differential equation becomes a separable equation. However, I can't find a solution for $n=3$ because it is not a Bernoulli equation nor an exact DE. If someone could help me, it would be great.

asked 2022-09-25

How do you find the general solution to $({x}^{2}+1)y\prime =xy$?

asked 2022-09-20

What is a solution to the differential equation $\frac{dy}{dx}={x}^{2}(1+y)$ with y=3 when x=0?

asked 2022-01-21

Are the following are linear equation?

$1.\text{}\mathrm{sin}\left(x\right)\frac{dy}{dx}-3y=0$

$2.\text{}\frac{{d}^{2}y}{{dx}^{2}}+\mathrm{sin}\left(x\right)\frac{dy}{dx}=\mathrm{cos}\left(x\right)$

asked 2022-02-17

Make use of vectors to re-write the following second order differential equation into a 1st order differential equation. (note: I do not need to solve it).

$2.1{x}^{-2}\frac{{d}^{2}y}{{dx}^{2}}-3{e}^{2x}{y}^{4}\frac{dy}{dx}=-6y$

where$y=4.2$ and $\frac{dy}{dx}=-3.1$ when $x=0.5$ .

Im not sure were to begin any help is greatly appreciated.

where

Im not sure were to begin any help is greatly appreciated.