excefebraxp
2022-09-12
Answered

Given the first term and the common difference of an arithmetic sequence. Find the first five terms and explicit formula: a1= -38, d=-100

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Lorenzo Aguilar

Answered 2022-09-13
Author has **18** answers

To calculate the consecutive terms just add d to $a}_{1$, so you get:

${a}_{2}={a}_{1}+r=-38+(-100)=-138$

${a}_{3}=a-2-100=-138-100=-238$

and so on

To find the formula just substitute $a}_{1$ and r in ${a}_{n}={a}_{1}+(n-1)r$

${a}_{n}=-38-100(n-1)=-38-100n+100=62-100n$

${a}_{1}=-38,{a}_{2}=-138,{a}_{3}=-238,{a}_{4}=-338,{a}_{5}=-438$

${a}_{2}={a}_{1}+r=-38+(-100)=-138$

${a}_{3}=a-2-100=-138-100=-238$

and so on

To find the formula just substitute $a}_{1$ and r in ${a}_{n}={a}_{1}+(n-1)r$

${a}_{n}=-38-100(n-1)=-38-100n+100=62-100n$

${a}_{1}=-38,{a}_{2}=-138,{a}_{3}=-238,{a}_{4}=-338,{a}_{5}=-438$

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