A survey of students revealed that 30% of them have a part-time job. If students are chosen at random what is the probability of the following events: That less than 2 have part time work? More than 3 are working part-time? None have a part-time job?

This is a question from a mock exam paper as I prepare for exams.

I guess I could start by imagining a number of 1000 college students surveyed with 300 having part-time jobs.

so for part (i) -> (30/100)(70/10)(70/10)(70/10)(70/10)=7%

That ain't right. Can someone shed some light on this?

This is a question from a mock exam paper as I prepare for exams.

I guess I could start by imagining a number of 1000 college students surveyed with 300 having part-time jobs.

so for part (i) -> (30/100)(70/10)(70/10)(70/10)(70/10)=7%

That ain't right. Can someone shed some light on this?