# Consider the following function. g(x)=-sqrt(x+2)-5

Consider the following function.
$g\left(x\right)=-\sqrt{x+2}-5$
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Karla Bautista
Given a function
$g\left(x\right)=-\sqrt{x+2}-5$
Here we can Analyze that function g(x) is obtained by shifting the basic function downwards by 5 units.
And also function g(x) is obtained by shifting the basic function f(x) by 2 units left.
So if we take
$f\left(x\right)=-\sqrt{x}$
Shift f(x) 5 unit downward
$f\left(x\right)-5=-\sqrt{x}-5\phantom{\rule{0ex}{0ex}}f\left(x+2\right)-5=-\sqrt{x+2}\phantom{\rule{0ex}{0ex}}f\left(x+2\right)-5=g\left(x\right)\phantom{\rule{0ex}{0ex}}f\left(x\right)=-\sqrt{x}$