$$g(x)=-\sqrt{x+2}-5$$

Kaleigh Ayers
2022-09-14
Answered

Consider the following function.

$$g(x)=-\sqrt{x+2}-5$$

$$g(x)=-\sqrt{x+2}-5$$

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Karla Bautista

Answered 2022-09-15
Author has **16** answers

Given a function

$$g(x)=-\sqrt{x+2}-5$$

Here we can Analyze that function g(x) is obtained by shifting the basic function downwards by 5 units.

And also function g(x) is obtained by shifting the basic function f(x) by 2 units left.

So if we take

$$f(x)=-\sqrt{x}$$

Shift f(x) 5 unit downward

$$f(x)-5=-\sqrt{x}-5\phantom{\rule{0ex}{0ex}}f(x+2)-5=-\sqrt{x+2}\phantom{\rule{0ex}{0ex}}f(x+2)-5=g(x)\phantom{\rule{0ex}{0ex}}f(x)=-\sqrt{x}$$

$$g(x)=-\sqrt{x+2}-5$$

Here we can Analyze that function g(x) is obtained by shifting the basic function downwards by 5 units.

And also function g(x) is obtained by shifting the basic function f(x) by 2 units left.

So if we take

$$f(x)=-\sqrt{x}$$

Shift f(x) 5 unit downward

$$f(x)-5=-\sqrt{x}-5\phantom{\rule{0ex}{0ex}}f(x+2)-5=-\sqrt{x+2}\phantom{\rule{0ex}{0ex}}f(x+2)-5=g(x)\phantom{\rule{0ex}{0ex}}f(x)=-\sqrt{x}$$

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