How can you desing a dice where the probability of 2 occurs is twice the probability of 1 occurs, the probability of 3 occurs is three times the probability of 1 occurs, the probability of 4 occurs is four times the probability of 1 occurs, the probability of 5 occurs is five times the probability of 1 occurs, and the probability of 6 occurs is six times the probability of 1 occurs?

tamola7f 2022-09-11 Answered
How can you desing a dice where the probability of 2 occurs is twice the probability of 1 occurs, the probability of 3 occurs is three times the probability of 1 occurs, the probability of 4 occurs is four times the probability of 1 occurs, the probability of 5 occurs is five times the probability of 1 occurs, and the probability of 6 occurs is six times the probability of 1 occurs?
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Answers (1)

Yaritza Cardenas
Answered 2022-09-12 Author has 20 answers
Step 1
Let probability of 1 occurs = x
P ( 1 ) = x
Then from given conditions
P ( 2 ) = 2 x P ( 3 ) = 3 x P ( 4 ) = 4 x P ( 5 ) = 5 x P ( 6 ) = 6 x P ( 1 ) + P ( 2 ) + P ( 3 ) + P ( 4 ) + P ( 5 ) + P ( 6 ) = 1 x + 2 x + 3 x + 4 x + 5 x + 6 x = 1 21 x = 1 x = 1 21 P ( 1 ) = 1 21 P ( 2 ) = 2 21 P ( 3 ) = 3 21 P ( 4 ) = 4 21 P ( 5 ) = 5 21 P ( 6 ) = 6 21
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