# Solve the equation of the line in slope-intercept form of the line perpendicular to y=1/3x+5 through (2, 1)

Solve the equation of the line in slope-intercept form of the line perpendicular to $y=\frac{1}{3}x+5$ through (2, 1)
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nizkem0c
The Line y2 perpendicular to Line y1, has as slope : -3.
y2 = -3x + b.
Find b by writing that Line y2 passing at point (2, 1):
1 = -3(2) = b -> b = 1 + 6 = 7
Line y2 = -3x + 7.