A logarithmic equation of the form logb x=y can be converted to the exponential equation \(\displaystyle{b}^{{{y}}}={x}.\)

Comparing \(\displaystyle{\log{{3}}}{1}={0}\) and logb x=y gives b=3, x=1, and y=0.

Therefore the exponential form \(\displaystyle{b}^{{{y}}}={x}{i}{s}{3}^{{{0}}}={1}.\)

Comparing \(\displaystyle{\log{{3}}}{1}={0}\) and logb x=y gives b=3, x=1, and y=0.

Therefore the exponential form \(\displaystyle{b}^{{{y}}}={x}{i}{s}{3}^{{{0}}}={1}.\)