# There is a fraction such that if 3 is added to the numerator, its value will be 1/3, and if 1 is subtracted from the denominator, its value with be 1/5. What is the fraction?

There is a fraction such that if 3 is added to the numerator, its value will be 1/3, and if 1 is subtracted from the denominator, its value with be 1/5. What is the fraction?\
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Baluttor7
Function is $\frac{x}{y}$
Now,
$\frac{x+3}{y}=\frac{1}{3}\phantom{\rule{0ex}{0ex}}⇒3\left(x+3\right)=y\phantom{\rule{0ex}{0ex}}⇒3x+9=y\phantom{\rule{0ex}{0ex}}\frac{x}{y-1}=\frac{1}{5}\phantom{\rule{0ex}{0ex}}\frac{x}{3x+9-1}=\frac{1}{5}\phantom{\rule{0ex}{0ex}}⇒5x-3x=8\phantom{\rule{0ex}{0ex}}⇒2x=8\phantom{\rule{0ex}{0ex}}x=4$