Harvey is 3 times as old as Jane. The sum of their ages is 48 years. What is the age of each?

Jaylen Dudley 2022-09-12 Answered
Harvey is 3 times as old as Jane. The sum of their ages is 48 years. What is the age of each?
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Answers (1)

mercuross8
Answered 2022-09-13 Author has 16 answers
Let Jane's' age=x
Hence, Harvey is 3× as old as Jane
Harvey's age = 3 × x = 3 x
Sum of their ages..
Jane's' age(x)+Harvey's age(3x)=48
x+3x=48
4x=48
Divide both sides by 4
4 x 4 = 48 4
4 x 4 = 48 4
x = 48 4
x=12
Substituting each values..
Jane's' age = x
Jane's' age= 12 years
and..
Harvey's age = 3x
Harvey's age= 3(12)
Harvey's age = 36 years

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