# Find the sum of the arithmetic series 6 + 12 + 18 + ... + 60

Find the sum of the arithmetic series 6 + 12 + 18 + ... + 60
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Yaritza Cardenas
${a}_{n}={a}_{1}+\left(n-1\right)d$
$60=6+\left(n-1\right)\left(6\right)$
$n=10$
Now that we know 60 is the 10th term , use the sum formula ...
sum=$=\frac{{a}_{1}+{a}_{n}}{2}×n$
sum$=\frac{6+60}{2}×10=330$