# In the school corridor, the length of which is 30 m, the width is 35 dm, it is necessary to replace the linoleum. What is the smallest number of linoleum rolls for this if the length of the linoleum roll is 12 m and the width is 160 cm?

In the school corridor, the length of which is 30 m, the width is 35 dm, it is necessary to replace the linoleum. What is the smallest number of linoleum rolls for this if the length of the linoleum roll is 12 m and the width is 160 cm?
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Konner Parker
The area of the corridor is
S=a*b
a= 30 m
b=35 dm
1 m = 10 dm, then
b= 35:10=3.5 m
$S=30\ast 3.5=105{m}^{2}$ corridor area
The linoleum roll has the following parameters:
a= 12 m
b= 160 cm
1 m=100 cm, so
b= 160:100=1.6 m
Area of 1 roll of linoleum
$12\ast 1.6=19.2{m}^{2}$
105:19.2≈5, 47 rolls, since 5 rolls is not enough, round up to 6 rolls.
The smallest quantity will be 6 rolls of linoleum.

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