How much is 1-cos 2x=?

How much is $1-\mathrm{cos}2x=$?
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Raina Russo
$1-\mathrm{cos}\left(2x\right);$
the unit can be expanded according to the basic trigonometric identity:
${\mathrm{sin}}^{2}\left(a\right)+{\mathrm{cos}}^{2}\left(a\right)=1;$
and the cosine of a double angle according to the corresponding formula:
$\mathrm{cos}\left(2x\right)={\mathrm{cos}}^{2}\left(a\right)-{\mathrm{sin}}^{2}\left(a\right);$
We get:
${\mathrm{sin}}^{2}\left(a\right)+{\mathrm{cos}}^{2}\left(a\right)-\left({\mathrm{cos}}^{2}\left(a\right)-{\mathrm{sin}}^{2}\left(a\right)\right);$
${\mathrm{sin}}^{2}\left(a\right)+{\mathrm{cos}}^{2}\left(a\right)-{\mathrm{cos}}^{2}\left(a\right)+{\mathrm{sin}}^{2}\left(a\right)=2{\mathrm{sin}}^{2}\left(a\right).$