a) find f(-1).

b) at what values x, f(x)=1?

c)Does the point A(1;0) belong to the graph of the function

Jamar Hays
2022-09-14
Answered

The function is given by the formula $$f(x)=2{x}^{2}-5x+3$$

a) find f(-1).

b) at what values x, f(x)=1?

c)Does the point A(1;0) belong to the graph of the function

a) find f(-1).

b) at what values x, f(x)=1?

c)Does the point A(1;0) belong to the graph of the function

You can still ask an expert for help

Illuddybopylu

Answered 2022-09-15
Author has **17** answers

$$a)f(-1)=2\ast (-1{)}^{2}-5\ast (-1)+3=2+5+3=10$$

$$b)2{x}^{2}-5x+3=1\iff 2{x}^{2}-5x+2=0$$

$$D={5}^{2}-4\ast 2\ast 2=25-16=9$$

x1=5+3/4=8/4=2

x2=5-3/4=2/4=0.5.

$$c)2\ast {1}^{2}-5\ast 1+3=0$$

2-5+3=0

-3+3=0

0=0

This point belongs to the graph.

$$b)2{x}^{2}-5x+3=1\iff 2{x}^{2}-5x+2=0$$

$$D={5}^{2}-4\ast 2\ast 2=25-16=9$$

x1=5+3/4=8/4=2

x2=5-3/4=2/4=0.5.

$$c)2\ast {1}^{2}-5\ast 1+3=0$$

2-5+3=0

-3+3=0

0=0

This point belongs to the graph.

mercuross8

Answered 2022-09-16
Author has **16** answers

$$F(x)=2{x}^{2}-5x+3$$

$$1)F(-1)=2\ast (-1{)}^{2}-5\ast (-1)+3=2+5+3=10$$

2)F(x)=1 find x

$$2{x}^{2}-5x+3=1$$

$$2{x}^{2}-5x+2=0$$

$${x}^{2}-2.5x+1=0$$

x1+x2=2.5

x1*x2=1

x1=0.5

x2=2

3)A(1.0)

x=1

$$2\ast {1}^{2}-5\ast 1+3=0$$

$$1)F(-1)=2\ast (-1{)}^{2}-5\ast (-1)+3=2+5+3=10$$

2)F(x)=1 find x

$$2{x}^{2}-5x+3=1$$

$$2{x}^{2}-5x+2=0$$

$${x}^{2}-2.5x+1=0$$

x1+x2=2.5

x1*x2=1

x1=0.5

x2=2

3)A(1.0)

x=1

$$2\ast {1}^{2}-5\ast 1+3=0$$

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