If the discriminant is 1, how many roots does the equation have? And how to solve: $$3{x}^{2}-13x+14$$ through the discriminant?

kybudmanqm
2022-09-12
Answered

If the discriminant is 1, how many roots does the equation have? And how to solve: $$3{x}^{2}-13x+14$$ through the discriminant?

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lilhova13b3

Answered 2022-09-13
Author has **12** answers

If the discriminant is equal to one, then the equation has two roots.

$$D={b}^{2}-4ac={13}^{2}-4\ast 3\ast 14=169-168=1$$

x1= (-b + root of D) / 2a = (13+1) / 2*3 = 14 / 6 = 7/3

x2= (-b - root of D) / 2a = (13-1) / 2*3 = 12/6 = 2

$$D={b}^{2}-4ac={13}^{2}-4\ast 3\ast 14=169-168=1$$

x1= (-b + root of D) / 2a = (13+1) / 2*3 = 14 / 6 = 7/3

x2= (-b - root of D) / 2a = (13-1) / 2*3 = 12/6 = 2

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