# If the discriminant is 1, how many roots does the equation have? And how to solve: 3x^(2)-13x+14 through the discriminant?

If the discriminant is 1, how many roots does the equation have? And how to solve: $3{x}^{2}-13x+14$ through the discriminant?
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lilhova13b3
If the discriminant is equal to one, then the equation has two roots.
$D={b}^{2}-4ac={13}^{2}-4\ast 3\ast 14=169-168=1$
x1= (-b + root of D) / 2a = (13+1) / 2*3 = 14 / 6 = 7/3
x2= (-b - root of D) / 2a = (13-1) / 2*3 = 12/6 = 2