plane depicted Parabola - Graph Square trinomial y=ax^(2)+bx+c. Known coordinates points A (-5; 0) and B (20; 0) - intersection points given parabola with axis Ox. Point C - Intersection given parabola with axis Oy - located above axes from. It is also known that Angle ACB-90^(circ). Specify the leading coefficient of the square trinomial (i.e. the number a)

Sasha Hess 2022-09-14 Answered
plane depicted
Parabola - Graph
Square trinomial
y = a x 2 + b x + c.
Known coordinates
points A (-5; 0) and B (20; 0)
- intersection points
given parabola with axis
Ox. Point C - Intersection
given parabola with axis
Oy - located above
axes from. It is also known that
Angle A C B 90 .
Specify the leading coefficient of the square trinomial (i.e. the number a)
You can still ask an expert for help

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

Solve your problem for the price of one coffee

  • Available 24/7
  • Math expert for every subject
  • Pay only if we can solve it
Ask Question

Answers (1)

Kristopher Beard
Answered 2022-09-15 Author has 18 answers
Let O be the origin of coordinates, then in a right triangle ABC a
CO height Since C A B = 90 C B A = O C B, then 4 O C B 4 C A B, whence we get that OC2 = AO OB = 100 and OC = 10. On the other hand, C has coordinates (0; c). By Vieta's theorem, for a square trinomial c = a × 1 × 2, that is,
10 = a (−5) 20, whence we obtain that a = −0, 1.
Answer: -0, 1

We have step-by-step solutions for your answer!

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

New questions