Jacob guessed a natural number greater than 99 but less than 1000. The sum of the first and last digits of this number is 1, and the product of the first and second digits is 7. What number did Jacob guess?

Question

gasskadeu7 · Accepted Answer

If the number is greater than 99 but less than 1000, then it is a three-digit number. Then let our number be abc = 100a + 10b + c.The first digit of a three-digit number cannot be zero, so   a  ≠  0The sum of the first and last digits of this number is 1.The number looks like   a  b  c  ⇒  a  +  c  =  1.The sum of two non-negative numbers can be equal to one only if one of the numbers is equal to zero.  a  ≠  0 and   a  +  c  =  1  ⇒  c  =  0Substitute c=0 and find a.  a  +  c  =  1  ⇒  a  =  1  −  c  =  1  −  0  =  1The product of the first and second digits is 7.The number looks like   a  b  c  ⇒  a  ∗  b  =  7Substitute a=1 and find b:  a  ∗  b  =  7  ⇒  b  =  7      /    a  =  7      /    1  =  7.a=1, b=7, c=0. Let&#039;s check the fulfillment of the conditions:  1  )  99  &amp;lt;  170  &amp;lt;  999  ⇒  99  &amp;lt;  a  b  c  &amp;lt;  999  2  )  1  +  0  =  1  ⇒  a  +  c  =  1  3  )  1  ∗  7  =  7  ⇒  a  b  =  7Accordingly, the desired number is 170.

Jacob guessed a natural number greater than 99 but less than 1000. The sum of the first and last digits of this number is 1, and the product of the first and second digits is 7. What number did Jacob guess?

Answered question

Answer & Explanation

New Questions in High school geometry