# The height BH of the rhombus ABCD divides its side AD into segments AH=44 and HD=11. Find the area of ​​the rhombus.

The height BH of the rhombus ABCD divides its side AD into segments AH=44 and HD=11. Find the area of ​​the rhombus.
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BH find from $\mathrm{△}$ ABH
$\mathrm{△}$ ABH- rectangular
according to the Pythagorean theorem
$B{H}^{2}=A{B}^{2}-A{H}^{2}$
AH=44 by condition
AB =AD = 55 (a rhombus has all sides equal)
$B{H}^{2}={55}^{2}-{44}^{2}=3025-1936=1089$
$BH=\sqrt{1089}=33$
S=55*33=1815