# sqrt(cos x)*sin x=0

$\sqrt{\mathrm{cos}x}﻿\ast \mathrm{sin}x=0$
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Lena Ibarra
$\sqrt{\mathrm{cos}x}﻿\ast \mathrm{sin}x=0$
$\sqrt{\mathrm{cos}x}=0⇒\mathrm{cos}x=0⇒{x}_{1}=\frac{\pi }{2}+\pi k$
$\mathrm{sin}x=0⇒{x}_{2}=\pi k$