# Solve the equation. 2 2/9: y=3 (19)/7: 3 1/3

Solve the equation.
$2\frac{2}{9}:y=3\frac{19}{7}:3\frac{1}{3}$
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2 2/9: y= 3 19/27: 3 1/3
Proportion; the product of the extreme terms of the proportion is equal to the product of the average
3 19/27• y= 2 2/9• 3 1/3
(3•27+19)/27•y= (2•9+2)/9• (3•3+1)/3
100/27•y= 20/9•10/3
Y= 20/9•10/3: 100/27
Y= 20/9•10/3• 27/100
{reduce 20 and 100 by 20; 9 and 27 by 9;}
Y= 1/1• 10/3• 3/5
{reduce 3 and 3 by 3; 10 and 5 by 5}
Y= 1/1• 2/1• 1/1
Y=2
Examination
2 2/9: y= 3 19/27: 3 1/3
20/9:2= 100/27:10/3
20/9• 1/2 = 100/27• 3/10
10/9•1/1= 10/9•1/1
10/9=10/9