Find expression values: $$n:21\frac{6}{23}-\frac{1}{47}m$$ at $$n=97,8$$ and $$m=31\frac{1}{3};$$

Jonah Jacobson
2022-09-13
Answered

Find expression values: $$n:21\frac{6}{23}-\frac{1}{47}m$$ at $$n=97,8$$ and $$m=31\frac{1}{3};$$

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Koen Henson

Answered 2022-09-14
Author has **17** answers

$$n:21\frac{6}{23}-\frac{1}{47}m$$ at $$n=97,8m=31\frac{1}{3}$$

$$97\frac{8}{10}:21\frac{6}{23}-\frac{1}{47}\ast 31\frac{1}{3}=$$

$$\frac{489}{5}\ast \frac{23}{489}-\frac{1}{47}\ast \frac{94}{3}=$$

$$\frac{489}{5}\ast \frac{23}{489}-\frac{1}{47}\ast \frac{94}{3}=\frac{23}{5}-\frac{2}{3}=$$

$$=\frac{69-10}{15}=\frac{59}{15}=3\frac{14}{15}$$

$$97\frac{8}{10}:21\frac{6}{23}-\frac{1}{47}\ast 31\frac{1}{3}=$$

$$\frac{489}{5}\ast \frac{23}{489}-\frac{1}{47}\ast \frac{94}{3}=$$

$$\frac{489}{5}\ast \frac{23}{489}-\frac{1}{47}\ast \frac{94}{3}=\frac{23}{5}-\frac{2}{3}=$$

$$=\frac{69-10}{15}=\frac{59}{15}=3\frac{14}{15}$$

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