# An insurance company crashed four cars in succession at 5 miles per hour. The cost of repair for each of the four crashes was ​$423, ​$456, ​$410, ​$237. Compute the​ range, sample​ variance, and sample standard deviation cost of repair.

An insurance company crashed four cars in succession at 5 miles per hour. The cost of repair for each of the four crashes was​$423, ​$456, ​$410, ​$237. Compute the​ range, sample​ variance, and sample standard deviation cost of repair.
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Range = smallest value - Largest value
=237-456
Range =219
Standart derivation $=\sqrt{\frac{{423}^{2}+{456}^{2}+{410}^{2}+{237}^{2}}{4}-\left(\frac{423-456+410+237}{4}\right)}\phantom{\rule{0ex}{0ex}}=85$
Standard deriviations = 85