An insurance company crashed four cars in succession at 5 miles per hour. The cost of repair for each of the four crashes was ​$423, ​$456, ​$410, ​$237. Compute the​ range, sample​ variance, and sample standard deviation cost of repair.

Hrefnui9 2022-09-13 Answered
An insurance company crashed four cars in succession at 5 miles per hour. The cost of repair for each of the four crashes was​$423, ​$456, ​$410, ​$237. Compute the​ range, sample​ variance, and sample standard deviation cost of repair.
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Answers (1)

trabadero2l
Answered 2022-09-14 Author has 15 answers
Range = smallest value - Largest value
=237-456
Range =219
Standart derivation = 423 2 + 456 2 + 410 2 + 237 2 4 ( 423 456 + 410 + 237 4 ) = 85
Standard deriviations = 85

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