# How do you find the first five terms of each sequence a_1=12, a_(n+1)=a_n−3?

How do you find the first five terms of each sequence ${a}_{1}=12$, ${a}_{n+1}={a}_{n}-3$?
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Grace Moses
${a}_{n+1}={a}_{n}-3$ and ${a}_{1}=12$
Find the first five terms.
This is a recursively defined sequence, which means you use the previous term to find the next.
The first term is ${a}_{1}=12$.
The 2nd term is ${a}_{2}={a}_{1+1}={a}_{1}-3=12-3=9$
The 3rd term is ${a}_{3}={a}_{2+1}={a}_{2}-3=9-3=6$
Note that you are subtracting 3 to find the next term.
So, ${a}_{4}=3$ and ${a}_{5}=0$.
The first 5 terms are $12,9,6,3,0$