# Find the equation of the line perpendicular to y=−2/5x−1 at x=−1

Find the equation of the line perpendicular to $y=-\frac{2}{5}x-1$ at x=−1
You can still ask an expert for help

• Live experts 24/7
• Questions are typically answered in as fast as 30 minutes
• Personalized clear answers

Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it

Griffin Dean
given that $y=-\frac{2}{5}x-1$
at x=−1
$y=-\frac{2}{5}\left(-1\right)-1=\frac{2}{5}-1=-\frac{3}{5}$
the line perpendicular has a slope, m where
$m\cdot \left(-\frac{2}{5}\right)=-1$ $\to m=\frac{5}{2}$
the equation is,
y=mx+c and plug in the values of x, y and m to find c
$-\frac{3}{5}=\frac{5}{2}\cdot \left(-1\right)+c$
$-\frac{3}{5}=-\frac{5}{2}+c$
$-\frac{3}{5}+\frac{5}{2}=c$$\to \frac{19}{10}$
therefore the equation is $y=\frac{5}{2}x+\frac{19}{10}$ $\to 10y=25x+19$