So the question looks like this A survey finds that 30% of all Canadians enjoy jogging. Of those Canadians who enjoy jogging, it is known that 40% of them enjoy swimming. For the 70% of Canadians who do not enjoy jogging, it is known that 60% of them enjoy swimming.

Suppose a Canadian is randomly selected. What is the probability that they enjoy exactly one of the two activities? Select the answer closest to yours.

I solved this using$$P(JoggingorSwimming)=P(Jogging)+P(Swimming)-P(Joggingandswimming)P(Jogging)=0.3P(Swimming)=0.54P(Joggingandswimming)=0.12$$

my answer was 0.72 but it was wrong. Please, what am I missing?

Suppose a Canadian is randomly selected. What is the probability that they enjoy exactly one of the two activities? Select the answer closest to yours.

I solved this using

my answer was 0.72 but it was wrong. Please, what am I missing?