 # Find the inverse Laplace transform of F(s)=(4s)/((s^2+5)^2−4s^2) Spactapsula2l 2022-09-14 Answered
Find the inverse Laplace transform of $F\left(s\right)=\frac{4s}{\left({s}^{2}+5{\right)}^{2}-4{s}^{2}}$, but I'm having trouble simplifying this fraction so I'm able to take the Laplace transform.
I simplified the denominator and got ${s}^{4}+6{s}^{2}+25$, but I'm not sure how that helps me.
I also tried looking at $4{s}^{2}$ and $\left(2s{\right)}^{2}$, but still am stuck.
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Hint
$\frac{4s}{{\left({s}^{2}+5\right)}^{2}-4{s}^{2}}=\frac{4s}{\left({s}^{2}+5+2s\right)\left({s}^{2}+5-2s\right)}=\frac{As+B}{{s}^{2}+5+2s}+\frac{Cs+D}{{s}^{2}+5-2s}$

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