24th term of an arithmetic sequence where a1=8 and a9= 56

lemondedeninaug

lemondedeninaug

Answered question

2022-09-12

24th term of an arithmetic sequence where a1=8 and a9= 56

Answer & Explanation

Everett Melton

Everett Melton

Beginner2022-09-13Added 12 answers

56 = 8 + ( 9 - 1 ) d
48 = 8 d
6 = d
The common difference is of 6. We can now find the 24th term using the formula t n = a + ( n - 1 ) d
t 24 = 8 + ( 24 - 1 ) 6
t 24 = 146
Thus, the 24th term is 146.

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