lemondedeninaug

2022-09-12

24th term of an arithmetic sequence where a1=8 and a9= 56

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Everett Melton

Expert

$56=8+\left(9-1\right)d$
$48=8d$
$6=d$
The common difference is of 6. We can now find the 24th term using the formula ${t}_{n}=a+\left(n-1\right)d$
${t}_{24}=8+\left(24-1\right)6$
${t}_{24}=146$
Thus, the 24th term is 146.

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