Suppose Player A and Player B are flipping a coin. Player A flips the coin 20 times, and Player B 40 times. What would be the probability that Player A gets 10 heads from his 20 flips, given that 20 heads were found in total.
I know we can use the binomial distribution to find the denominator(20 heads in 60 flips), but I'm wondering what exactly would b in the numerator. Would I use the binomial distribution as well?
This is my denominator:
( 60 20 ) 0.5 20 ( 1 .5 ) 40

Do you have a similar question?

Recalculate according to your conditions!

Answer & Explanation




2022-09-12Added 15 answers

Step 1
Trusting that you mean "exactly" in each instance (so "exactly" 20 heads tossed, etc.) then the numerator is the joint probability that A throws exactly 10 Heads AND B throws exactly 10.
Step 2
By independence, this joint probability is just a product and the two factors can easily be computed from the binomial distribution.

Still Have Questions?

Ask Your Question

Free Math Solver

Help you to address certain mathematical problems

Try Free Math SolverMath Solver Robot

Ask your question.
Get your answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?