# 2^{7}times sqrtfrac{1}{4}

${2}^{7}×\sqrt{\frac{1}{4}}$
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$\sqrt{1}=1--------------\left(1x1=1\right)$
$\sqrt{4}=2-------------\left(2x2=4\right).$
$\sqrt{\frac{1}{4}}=\frac{\frac{\sqrt{1}}{\sqrt{4}}}{=}\frac{1}{2}$
thus
${2}^{7}x\sqrt{\frac{1}{4}}={2}^{7}x\frac{1}{2}=\frac{{2}^{7}}{2}=$
$\frac{{2}^{7}}{{2}^{1}}={\left(2\right)}^{7-1}={2}^{6}=64$. --------- rule -- $\frac{{X}^{m}}{{X}^{n}}={X}^{m-n}$.