The initial value problem is given by y‘= (1 - 2x)y^2 ; y(0) = -1/6 solving its particular solution by variable separable, the value for the constant C is:

Janine Collamat
2022-09-17

The initial value problem is given by y‘= (1 - 2x)y^2 ; y(0) = -1/6 solving its particular solution by variable separable, the value for the constant C is:

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