I got a question about the use of Chi Square test. Let's assume I am conducting a survey. And I have a question: "Have you ever heard of the Internet"? The possible answers are: "Yes", "No", "Not sure" and I have 3 different age groups for my respondents: "<18", "18 When I want to do a Chi Square test to see if the age factor has an effect, can I just conduct this test on the "Yes" part? Or Do I need to include all the variables?

spremani0r

spremani0r

Answered question

2022-09-11

I got a question about the use of Chi Square test. Let's assume I am conducting a survey. And I have a question: "Have you ever heard of the Internet"?
The possible answers are: "Yes", "No", "Not sure" and I have 3 different age groups for my respondents: "<18", "18
When I want to do a Chi Square test to see if the age factor has an effect, can I just conduct this test on the "Yes" part? Or Do I need to include all the variables?

Answer & Explanation

Zayden Dorsey

Zayden Dorsey

Beginner2022-09-12Added 18 answers

Inorder to use Chi Square test you need to have two variables. In your example these variables are age and use/no use of internet. Hence you have to use 'yes','no,'not sure'.
Lucille Douglas

Lucille Douglas

Beginner2022-09-13Added 1 answers

It depends on what you want to measure.
You could test whether or not the distribution of "Yes"/"No"/"Not sure" is significantly different from what would occur under the null hypothesis - say, an equal distribution of Y/N/DKs. This is the so-called test for homogeneity use of the χ 2 -test.
However, in most cases one uses the χ 2 -test to test for independence between two variables. Stochastic independence is defined by Pr ( A B ) = Pr ( A ) Pr ( B ) - this forms our null hypothesis. This directly translates into the expected cell count E x i of the cell xi as the product of the marginal probabilities times the number of observations. The test statistic is then ( E x i O x i ) 2 E x i , which is χ k 2 -distributed with k being the number of rows minus 1 times the number of columns minus 1.

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