Question

Eight farmers each had eight farms that each had eight dogs that each had eight puppies that each had eight fleas. How many total legs are there?

Factors and multiples
ANSWERED
asked 2020-12-12
Eight farmers each had eight farms that each had eight dogs that each had eight puppies that each had eight fleas. How many total legs are there?

Answers (2)

2020-12-13
no of farmers = 8
no of farms each farmer had = 8 therefore, total no of farms = 8 x 8 = 64
no of dogs each farm had = 8 therefore, total no of dogs = 64 x 8 = 512
no of puppies each dog had = 8 therefore, total no of puppies = 512 x 8 = 4096
no of fleas each puppy had = 8 therefore, total no of fleas = 4096 x 8 = 32,768
total no of legs of 512 dogs = 512 x 4 = 2048 total no of legs of 4096 puppies = 4096 x 4 = 16384 total no of legs of 32768 fleas = 32768 x 6 = 131072
Hence, total number of legs present = 2048 + 16384 + 131072 = 149,504 legs
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Best answer
2021-09-23
Farmers: 8

Each farmer had 8 farms: 8x8=64 farms

Each farm had 8 dogs: 64x8=512 dogs

Each dog had 8 puppies: 512x8=4096 puppies

Each puppy had 8 fleas: 4096x8=32,768 fleas

8 farmers x 2 legs each = 16 legs

512 dogs x 4 legs each = 2048 legs

4096 puppies x 4 legs each= 16,384 legs

32,768 fleas x 6 legs each = 196,608 legs

16+2048+16,384+196,608= 215, 056 legs

There are a total of 215,056 legs!
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