Suppose that in a city of 100 people, a survey conclude that 30 of them do not agree (says 'no') with the building of a new luxury apartment. If you randomly chose 12 people in the city what is the probability that 2 to 6 of them are those who disagree with the building of the new luxury apartment? This seemed to be a binomial probability question.... though I fail to recall how to do so. bonus point if you know how to solve this in minitab!

sdentatoiz

sdentatoiz

Answered question

2022-09-08

Suppose that in a city of 100 people, a survey conclude that 30 of them do not agree (says 'no') with the building of a new luxury apartment. If you randomly chose 12 people in the city what is the probability that 2 to 6 of them are those who disagree with the building of the new luxury apartment?
This seemed to be a binomial probability question.... though I fail to recall how to do so.
bonus point if you know how to solve this in minitab!

Answer & Explanation

ivice7u

ivice7u

Beginner2022-09-09Added 18 answers

The total number of ways to choose 12 out of 100 people is:
( 100 12 )
The number of ways to choose them with 2 to 6 disagreeing is:
n = 2 6 ( 30 n ) ( 100 30 12 n )
So the probability of choosing them with 2 to 6 disagreeing is:
n = 2 6 ( 30 n ) ( 100 30 12 n ) ( 100 12 ) 89.86 %
Kathryn Sanchez

Kathryn Sanchez

Beginner2022-09-10Added 1 answers

n = 100 , p = 0.3 , q = 1 p = 1 0.3 = 0.7. We find: P ( 2 x 6 ), and this equals to:
P ( 2 ) + P ( 3 ) + P ( 4 ) + P ( 5 ) + P ( 6 ) = k = 2 6 ( 100 k ) 0.3 k 0.7 100 k

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