Find a partial fraction for complex roots using the second order polynomial ((s^2+s+1))/((s^2+4s+3)(s+1))

Radarfoto67

Radarfoto67

Answered question

2022-09-09

Find a partial fraction for complex roots using the second order polynomial ( s 2 + s + 1 ) ( s 2 + 4 s + 3 ) ( s + 1 )

Answer & Explanation

detegerex

detegerex

Beginner2022-09-10Added 16 answers

s 2 + s + 1 ( s + 1 ) ( s 2 + 4 s + 3 ) = 7 4 ( s + 3 ) 3 4 ( s + 1 ) + 1 2 ( s + 1 ) 2
tophergopher3wo

tophergopher3wo

Beginner2022-09-11Added 5 answers

Note that
s 2 + s + 1 ( s + 1 ) ( s 2 + 4 s + 3 ) = A s + 1 + B ( s + 1 ) 2 + C s + 3
I have found A = 3 / 4, B = 1 / 2 and C = 7 / 4

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