# Simplify the expression 12(x^{−6})y^{10⋅3}(x^{7})y A) 15xy^{11} B) 36xy^{10} C) 36x−42y^{10} D) 36xy^{11}

Simplify the expression
$12\left({x}^{-6}\right){y}^{10\cdot 3}\left({x}^{7}\right)y$
$A\right)15x{y}^{11}$
$B\right)36x{y}^{10}$
$C\right)36x-42{y}^{10}$
$D\right)36x{y}^{11}$
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yagombyeR

$12\left({x}^{-6}\right){y}^{10×3}\left({x}^{7}\right)y=\left(12×3\right)\left({x}^{-6}×{x}^{7}\right)\left({y}^{10}×y\right)=36\left({x}^{-6}+7\right){y}^{10+1}=36x{y}^{11}$
The correct answer is then $36x{y}^{11}$