factor x^4+4x^3-x^2+16x-20=0

reinzogoq

reinzogoq

Answered question

2022-09-06

factor x^4+4x^3-x^2+16x-20=0

Answer & Explanation

Kenny Kramer

Kenny Kramer

Beginner2022-09-07Added 14 answers

1+4-1+16-20 = 0 -> one factor is (x-1) , dividing by (x-1) we can fine other factors as well:
x^4+4x^3-x^2+16x-20 = (x-1)(x+5)(x^2+4)

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